Definition: This calculator computes the energy cost per hour (\( C \)) for pumping water, based on the volume flow (\( Q \)), differential head (\( h \)), cost rate per kWh (\( c \)), pump efficiency (\( \mu_p \)), and motor efficiency (\( \mu_m \)).
Purpose: It is used in mechanical engineering to estimate the operational cost of pumping water, aiding in system design, cost optimization, and energy efficiency analysis.
The calculator uses the relationship:
Where:
Explanation: Enter the volume flow, differential head, cost rate per kWh, pump efficiency, and motor efficiency in the chosen units. The flow is converted to US gpm, and the head is converted to feet. The cost per hour is calculated using \( C = 0.746 \frac{Q h c}{3960 \mu_p \mu_m} \). Results are displayed with 5 decimal places, using scientific notation if the value exceeds 100,000 or is less than 0.0001. For default inputs (\( Q = 100 \, \text{gpm} \), \( h = 100 \, \text{ft} \), \( c = 0.12 \, \text{USD/kWh} \), \( \mu_p = 0.8 \), \( \mu_m = 0.9 \)), the calculated cost is approximately 0.25833 USD/hour.
Details: Calculating the energy cost for pumping water is essential for managing operational expenses, optimizing pump and motor efficiencies, and ensuring cost-effective system design in water pumping applications.
How do I calculate the energy cost for pumping water?
Enter the volume flow (\( Q \)), differential head (\( h \)), cost rate per kWh (\( c \)), pump efficiency (\( \mu_p \)), and motor efficiency (\( \mu_m \)) in the chosen units. Compute the cost using the formula \( C = 0.746 \frac{Q h c}{3960 \mu_p \mu_m} \). The result will be in USD/hour, EUR/hour, or GBP/hour, depending on the cost rate unit.
What does the energy cost for pumping water represent?
The energy cost (\( C \)) represents the hourly cost of electricity required to pump water at a given flow rate and head, factoring in the efficiencies of the pump and motor, which is crucial for operational budgeting.
What is the formula for energy cost calculation?
The formula is \( C = 0.746 \frac{Q h c}{3960 \mu_p \mu_m} \), where \( Q \) is the flow in US gpm, \( h \) is the head in feet, \( c \) is the cost rate per kWh, \( \mu_p \) is the pump efficiency, and \( \mu_m \) is the motor efficiency. The result is in cost per hour.
Can I use different units for flow, head, and cost rate?
Yes, the calculator supports flow in US gpm, L/s, or m³/h, head in feet, meters, centimeters, inches, or yards, and cost rate in USD/kWh, EUR/kWh, or GBP/kWh. All inputs are converted to their base units for calculation.
What happens if I enter zero for flow, pump efficiency, or motor efficiency?
Entering zero for the flow (\( Q \)), pump efficiency (\( \mu_p \)), or motor efficiency (\( \mu_m \)) will result in the calculation not being performed, as the formula involves division by these values. All must be greater than zero for a valid result.