Hose Pressure Loss Calculator

Pressure Loss Formula:

\[ \Delta P = \frac{f \times L \times \rho \times V^2}{2 \times D \times 144} \]

Friction Factor (f):

Hose Length (L):

Fluid Density (ρ):

lb/ft³

Flow Velocity (V):

ft/s

Hose Diameter (D):

Pressure Loss (ΔP): psi

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1. What is a Hose Pressure Loss Calculator?

Definition: This calculator estimates the pressure loss in a hose using the Darcy-Weisbach equation.

Purpose: It helps engineers and technicians determine the pressure drop in fluid systems for proper pump sizing and system design.

2. How Does the Calculator Work?

The calculator uses the Darcy-Weisbach equation:

\[ \Delta P = \frac{f \times L \times \rho \times V^2}{2 \times D \times 144} \]

Where:

\( \Delta P \) — Pressure loss (psi)
\( f \) — Dimensionless friction factor
\( L \) — Hose length (ft)
\( \rho \) — Fluid density (lb/ft³)
\( V \) — Flow velocity (ft/s)
\( D \) — Hose diameter (ft)

Explanation: The equation calculates the pressure drop due to friction in a pipe or hose.

3. Importance of Pressure Loss Calculation

Details: Accurate pressure loss calculations ensure proper system performance, prevent pump overload, and help maintain desired flow rates.

4. Using the Calculator

Tips: Enter the friction factor (default 0.02 for turbulent flow), hose length, fluid density (default 62.4 lb/ft³ for water), flow velocity, and hose diameter. All values must be > 0.

5. Frequently Asked Questions (FAQ)

Q1: How do I determine the friction factor?
A: For turbulent flow, use the Moody chart or Colebrook equation. For smooth pipes, 0.02 is a typical starting value.

Q2: What units should I use?
A: The calculator requires consistent units: feet for length/diameter, lb/ft³ for density, and ft/s for velocity.

Q3: Does this account for fittings and valves?
A: No, this calculates only straight pipe losses. For fittings, use equivalent length methods or K-factor methods.

Q4: What's a typical velocity for water systems?
A: 4-8 ft/s is common for water in industrial applications to balance pressure loss and erosion concerns.

Q5: How does diameter affect pressure loss?
A: Pressure loss is inversely proportional to diameter - smaller diameters create significantly higher losses.